x^2-3x^2+2=2

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Solution for x^2-3x^2+2=2 equation: 



x^2-3x^2+2=2

We move all terms to the left:

x^2-3x^2+2-(2)=0

We add all the numbers together, and all the variables

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$

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